[Codility] Lesson3. FrogJmp (C#)

문제: app.codility.com/programmers/lessons/3-time_complexity/frog_jmp/

FrogJmp coding task - Learn to Code - Codility

 

            if (X >= 1 && X <= 1000000000 && Y >= 1 && Y <= 1000000000 && D >= 1 && D <= 1000000000 && X <= Y)
            {
                double calc = (Y - X) / D;
                if ((Y - X) % D == 0)
                    return (int)calc;
                else
                    return (int)calc + 1;
            }

            return 0;